4x^2+3x^2+25=360

Solution for 4x^2+3x^2+25=360 equation:

4x^2+3x^2+25=360

We move all terms to the left:

4x^2+3x^2+25-(360)=0

We add all the numbers together, and all the variables

7x^2-335=0

a = 7; b = 0; c = -335;
Δ = b2-4ac
Δ = 02-4·7·(-335)
Δ = 9380
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9380}=\sqrt{4*2345}=\sqrt{4}*\sqrt{2345}=2\sqrt{2345}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{2345}}{2*7}=\frac{0-2\sqrt{2345}}{14}
=-\frac{2\sqrt{2345}}{14}
=-\frac{\sqrt{2345}}{7}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{2345}}{2*7}=\frac{0+2\sqrt{2345}}{14}
=\frac{2\sqrt{2345}}{14}
=\frac{\sqrt{2345}}{7}
$